9f^2+7f+1=0

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Solution for 9f^2+7f+1=0 equation: 



9f^2+7f+1=0

a = 9; b = 7; c = +1;
Δ = b2-4ac
Δ = 72-4·9·1
Δ = 13
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{13}}{2*9}=\frac{-7-\sqrt{13}}{18}
$


$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{13}}{2*9}=\frac{-7+\sqrt{13}}{18}
$

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